Re: [PATCH v2 5/5] sparse-index: improve lstat caching of sparse paths

> "Derrick Stolee via GitGitGadget" <gitgitgadget@gmail.com> writes:
>> +/**
>> + * Return the length of the largest common substring that ends in a
> 
> "largest" here is understandable (it means longest).
> 
>> + * slash ('/') to indicate the largest common parent directory. Returns
> 
> here I find it a bit confusing.  It is the deepest common parent
> directory between the two (or "the common parent directory with the
> longest path"), but my initial reaction was "largest common parent
> directory?  wouldn't the root level by definition the 'largest'
> (having the largest number of paths underneath) directory that is
> common?)".

>> + * zero if no common directory exists.
>> + */
>> +static size_t max_common_dir_prefix(const char *path1, const char *path2)
>> +{
>> +	size_t common_prefix = 0;
>> +	for (size_t i = 0; path1[i] && path2[i]; i++) {
>> +		if (path1[i] != path2[i])
>> +			break;
>> +
>> +		/*
>> +		 * If they agree at a directory separator, then add one
>> +		 * to make sure it is included in the common prefix string.
>> +		 */
>> +		if (path1[i] == '/')
>> +			common_prefix = i + 1;
>> +	}
>> +
>> +	return common_prefix;
>> +}
> 
> Looking good.  I assume that these two paths are relative to the
> top-level of the working tree (in other words, they do not begin
> with a slash)?

>>   static int path_found(const char *path, struct path_found_data *data)
>>   {
>> ...
>> +	 * At this point, we know that 'path' doesn't exist, and we know that
>> +	 * the parent directory of 'data->dir' does exist. Let's set 'data->dir'
>> +	 * to be the top-most non-existing directory of 'path'. If the first
>> +	 * parent of 'path' exists, then we will act as though 'path'
>> +	 * corresponds to a directory (by adding a slash).
>>   	 */
>> -	newdir = strrchr(path, '/');
>> -	if (!newdir)
>> -		return 0; /* Didn't find a parent dir; just return 0 now. */
>> +	common_prefix = max_common_dir_prefix(path, data->dir.buf);
>> ...
>> +	strbuf_setlen(&data->dir, common_prefix);
>> +	while (1) {
> 
> Oooh, nice.  So you learned /a/b/c/d did not exist, so check /a/b/c,
> and then /a/b/ and stop, because you know /a does exist already.
> With luck, our next query is for /a/b/c/e or for /a/b/f, and knowing
> that /a/b/ does not exist would allow us to say "no, they do not
> exist" without having to lstat().  OK.