Re: [PATCH 07/20] midx: check size of pack names chunk
- From
Taylor Blau <me@ttaylorr.com>
- Date
- Oct 11, 2023, 14:52 UTC
- Message-ID
- <ZSa2nbVDTXvFZvSx@nand.local>
- In-Reply-To
- <20231009210514.GG3282181@coredump.intra.peff.net>
On Mon, Oct 09, 2023 at 05:05:14PM -0400, Jeff King wrote:
Show 8 quoted lines
> @@ -176,9 +176,16 @@ struct multi_pack_index *load_multi_pack_index(const char *object_dir, int local
>
> cur_pack_name = (const char *)m->chunk_pack_names;
> for (i = 0; i < m->num_packs; i++) {
> + const char *end;
> + size_t avail = m->chunk_pack_names_len -
> + (cur_pack_name - (const char *)m->chunk_pack_names);
> +This patch all looks good to me, but reading this hunk gave me a little bit of pause. I was wondering what might happen if chunk_pack_names_len was zero, and subtracting some other non-zero size_t from it might cause us to wrap around.
But I think that's a non-issue here, since we'd set cur_pack_name to the beginning of the chunk, and compute avail as 0 - (m->chunk_pack_names - m->chunk_pack_names), and get 0 back, causing our memchr() lookup below to fail, and for us to report this chunk is garbage.
And since cur_pack_name monotonically increases, I think that there is an inductive argument to be made that this subtraction is always safe to do. But it couldn't hurt to do something like:
size_t read = cur_pack_name - (const char *)m->chunk_pack_names;
size_t avail = m->chunk_pack_names_len; if (read > avail)
die("...");
avail -= read;to make absolutely sure that we would never underflow here.
Thanks, Taylor