Re: [PATCH] Makefile: set USE_PIC on Linux x86_64 for linking with Git.pm
- From
- Marco Roeland <marco.roeland@xs4all.nl>
- Date
- Jun 28, 2006, 19:21 UTC
- Message-ID
- <20060628192145.GD5713@fiberbit.xs4all.nl>
- In-Reply-To
- <7virml14za.fsf@assigned-by-dhcp.cox.net>
On Wednesday June 28th 2006 Junio C Hamano wrote:
Show 18 quoted lines
> >> ifeq ($(uname_S),Linux) > >> NO_STRLCPY = YesPlease > >> + ifneq (,$(findstring x86_64,$(uname_M))) > >> + USE_PIC = YesPlease > >> + endif > >> endif > > In other words, I am wondering why you did not do this more > obvious one: > > ifeq ($(uname_M),x86_64) > USE_PIC = YesPlease > endif > > My suspicion is that you protected that in Linux on purpose > because you know that my version would break for somebody else, > or because you are trying to be cautious not to break other > platforms you do not have access to, and I cannot tell which.
Sorry for the confusion. Yes that construct is much more readable. I copy and pasted it from another section in the Makefile and adapted it to this use. I tested it and it worked so I decided no to change it anymore. So that clears up the syntactical issue.
I certainly do not know cases outside Linux where this might break on x86-64. I just tried to limit it to the case I could test. But perhaps someone with an x86-64 BSD or Solaris might try it?
To paraphrase Dave Jones: I type 'make', it fails. Some 'git log' later I realise I have to manually define 'USE_PIC'. Hey, why doesn't it work automagically? Some 'git grep' and I spot a construct for specific (sub)platforms. Monkey see, monkey do. I type 'make', it works and monkey sends patch! Thats it! No subtleties involved;-)
-- Marco Roeland