Re: why is git destructive by default? (i suggest it not be!)

To re-ask the same question I asked in my last post, using your ascii pictures...

Let's assume we're here..

.<---.<---.<---A<---X<---Y <--- master \ \--B<---C <--- customer_A_branch <=== HEAD

And this person and everyone else moves their head pointers back to master without merging:

.<---.<---.<---A<---X<---Y <--- master <=== HEAD \ \--B<---C <--- customer_A_branch

Now, five years down the road, our tree looks like:

.<---A<---X<---Y<---.<--.<--.(3 years of changes)<---ZZZ<--- master <=== HEAD \ \--B<---C <--- customer_A_branch

And someone does:

git-branch -f customer_A_branch ZZZ

To bring us to:

.<---A<---X<---Y<---.<--.(3 years of changes)<---ZZZ<--- master <=== HEAD \ \ \--B<---C \-- customer_A_branch

..at this point, will a GC keep "B<--C", or garbage collect the commits and throw them away?