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Re: [PATCH 1/1] Don't free remote->name after fetch

From
Junio C Hamano <gitster@pobox.com>
Date
Jun 13, 2016, 22:25 UTC
Message-ID
<xmqqbn34buak.fsf@gitster.mtv.corp.google.com>
In-Reply-To
<1465841837-31604-1-git-send-email-kmcguigan@twopensource.com>
kmcguigan@twopensource.com writes:
Show 7 quoted lines
> From: Keith McGuigan <kmcguigan@twopensource.com>
>
> The string_list gets populated with the names from the remotes[] array,
> which are not dup'd and the list does not own.
>
> Signed-of-by: Keith McGuigan <kmcguigan@twopensource.com>
> ---
For names that come from remote_get()->name, e.g.
    static int get_one_remote_for_fetch(struct remote *remote, void *priv)
    {
            struct string_list *list = priv;
            if (!remote->skip_default_update)
                    string_list_append(list, remote->name);
            return 0;
    }

you are correct that this is borrowed memory we are not allowed to free. But is borrowing from remote->name the only way this list is populated? For example, what happens in add_remote_or_group(), which does this?

    struct remote_group_data {
            const char *name;
            struct string_list *list;
    };
    static int get_remote_group(const char *key, const char *value, void *priv)
    {
            struct remote_group_data *g = priv;
            if (skip_prefix(key, "remotes.", &key) && !strcmp(key, g->name)) {
                    /* split list by white space */
                    while (*value) {
                            size_t wordlen = strcspn(value, " \t\n");
                            if (wordlen >= 1)
                                    string_list_append(g->list,
                                                       xstrndup(value, wordlen));
This newly allocated piece of memory is held by g->list, which was...
                            value += wordlen + (value[wordlen] != '\0');
                    }
            }
            return 0;
    }
    static int add_remote_or_group(const char *name, struct string_list *list)
    {
            int prev_nr = list->nr;
            struct remote_group_data g;
            g.name = name; g.list = list;
... passed as a callback parameter from here.
            git_config(get_remote_group, &g);
            if (list->nr == prev_nr) {
                    struct remote *remote = remote_get(name);
                    if (!remote_is_configured(remote))
                            return 0;
                    string_list_append(list, remote->name);

This makes remote->name borrowed, which we cannot free() as you point out.

            }
            return 1;
    }

So, while I agree that many should not be freed, this change makes the code leak some at the same time.

Show 16 quoted lines
>  builtin/fetch.c | 2 --
>  1 file changed, 2 deletions(-)
>
> diff --git a/builtin/fetch.c b/builtin/fetch.c
> index 630ae6a1bb78..181da5a2e7a3 100644
> --- a/builtin/fetch.c
> +++ b/builtin/fetch.c
> @@ -1347,8 +1347,6 @@ int cmd_fetch(int argc, const char **argv, const char *prefix)
>  		argv_array_clear(&options);
>  	}
>  
> -	/* All names were strdup()ed or strndup()ed */
> -	list.strdup_strings = 1;
>  	string_list_clear(&list, 0);
>  
>  	close_all_packs();
Previous: kmcguigan@twopensource.comNext: Keith McGuigan
Message 2 of 5 in “Don't free remote->name after fetch”
  1. 1/1 Don't free remote->name after fetchkmcguigan@twopensource.com, Jun 13, 2016
  2. Junio C HamanoJun 13, 2016
  3. Keith McGuiganJun 14, 2016
  4. Jeff KingJun 14, 2016
  5. Junio C HamanoJun 14, 2016

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