Re: Fully peel tags via for-each-ref?

From: Junio C Hamano <gitster@pobox.com>
Date: Aug 20, 2019, 05:50 UTC
Message-ID: <xmqq8srowfkv.fsf@gitster-ct.c.googlers.com>
In-Reply-To: <CAGyf7-GBx3FSCQTipmkNBtnwMANg5A0FXiiPc2az0NiRLRT+xg@mail.gmail.com>

Bryan Turner <bturner@atlassian.com> writes:

> Is there any way, with "git for-each-ref", to output the "fully"
> peeled SHA of a tag's ultimate target, regardless of how many layers
> must be traversed?

I do not think I wrote it to allow different degree of peeling, not because I wanted to explicitly forbid a use case for tags that tag another tag, but simply because I didn't think of anybody using it and didn't see need to support such tags.

If %(*<stuff>) does not peel fully (I do not recall what I did offhand), because all other things in Git (like $X~0, $X^{tree}, etc.) fully peel the outer object until they get to what they want, it may even be OK to declare it a bug and "fix" the notation to fully peel tags. I dunno.