From: Junio C Hamano <gitster@pobox.com>
Date: Tue, 20 Aug 2019 05:50:24 GMT
Subject: Re: Fully peel tags via for-each-ref?
Message-ID: <xmqq8srowfkv.fsf@gitster-ct.c.googlers.com>
In-Reply-To: <CAGyf7-GBx3FSCQTipmkNBtnwMANg5A0FXiiPc2az0NiRLRT+xg@mail.gmail.com>

Bryan Turner <bturner@atlassian.com> writes:

> Is there any way, with "git for-each-ref", to output the "fully"
> peeled SHA of a tag's ultimate target, regardless of how many layers
> must be traversed?

I do not think I wrote it to allow different degree of peeling, not
because I wanted to explicitly forbid a use case for tags that tag
another tag, but simply because I didn't think of anybody using it
and didn't see need to support such tags.

If %(*<stuff>) does not peel fully (I do not recall what I did
offhand), because all other things in Git (like $X~0, $X^{tree},
etc.) fully peel the outer object until they get to what they want,
it may even be OK to declare it a bug and "fix" the notation to
fully peel tags.  I dunno.