Re: [PATCH v2] strvec: `strvec_splice()` to a statically initialized vector
- From
Junio C Hamano <gitster@pobox.com>
- Date
- Dec 9, 2024, 07:33 UTC
- Message-ID
- <xmqq5xntpaya.fsf@gitster.g>
- In-Reply-To
- <20241209021556.GA1293399@coredump.intra.peff.net>
Jeff King <peff@peff.net> writes:
Show 18 quoted lines
> I think it is this off-by-one: > > diff --git a/strvec.c b/strvec.c > index 62283fcef2..d67596e571 100644 > --- a/strvec.c > +++ b/strvec.c > @@ -66,7 +66,7 @@ void strvec_splice(struct strvec *array, size_t idx, size_t len, > array->v = NULL; > ALLOC_GROW(array->v, array->nr + (replacement_len - len) + 1, > array->alloc); > - array->v[array->nr + (replacement_len - len) + 1] = NULL; > + array->v[array->nr + (replacement_len - len)] = NULL; > } > for (size_t i = 0; i < len; i++) > free((char *)array->v[idx + i]); > > We allocate with "+1" to account for the NULL, but when we index to > assign the slot, we count from 0.
Ah, of course. Usually v[len] is what you never touch (because 0..(len-1) are the valid index into an array of length len), unless the array has a sentinel at the end, in which case you have the sentinel there. v[len + 1] would obviously be out of bounds.
> Or more concretely for the test case, we are adding 1 replacement item > to a 0-element array, and the result will have 1 item. So we allocate > 2 slots, and slot 1 is the NULL.
Thanks.