Re: SHA1 hash safety
On Tue, 19 Apr 2005, David Meybohm wrote:
> But doesn't this require assuming the distribution of MD5 is uniform,
> and don't the papers finding collisions in less show it's not? So, your
> birthday-argument for calculating the probability wouldn't apply, because
> it rests on the assumption MD5 is uniform, and it isn't.
No, the collision papers don't show this at all.
--scott
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