Re: "git fsck" not detecting garbage at the end of blob object files...

> On Sat, Jan 07, 2017 at 10:47:03PM +0100, Dennis Kaarsemaker wrote:
>> On Sat, 2017-01-07 at 07:50 -0500, John Szakmeister wrote:
>> > I was perusing StackOverflow this morning and ran across this
>> > question: http://stackoverflow.com/questions/41521143/git-fsck-full-only-checking-directories/
>> >
>> > It was a simple question about why "checking objects" was not
>> > appearing, but in it was another issue.  The user purposefully
>> > corrupted a blob object file to see if `git fsck` would catch it by
>> > tacking extra data on at the end.  `git fsck` happily said everything
>> > was okay, but when I played with things locally I found out that `git
>> > gc` does not like that extra garbage.  I'm not sure what the trade-off
>> > needs to be here, but my expectation is that if `git fsck` says
>> > everything is okay, then all operations using that object (file)
>> > should work too.
>> >
>> > Is that unreasonable?  What would be the impact of fixing this issue?
>>
>> If you do this with a commit object or tree object, fsck does complain.
>> I think it's sensible to do so for blob objects as well.
>
> The existing extra-garbage check is in unpack_sha1_rest(), which is
> called as part of read_sha1_file(). And that's what we hit for commits
> and trees. However, we check the sha1 of blobs using the streaming
> interface (in case they're large). I think you'd want to put a similar
> check into read_istream_loose(). But note if you are grepping for it, it
> is hidden behind a macro; look for read_method_decl(loose).

> I'm actually not sure if this should be downgrade to a warning. It's
> true that it's a form of corruption, but it doesn't actually prohibit us
> from getting the data we need to complete the operation. Arguably fsck
> should be more picky, but it is just relying on the same parse_object()
> code path that the rest of git uses.
>
> I doubt anybody cares too much either way, though. It's not like this is
> a common thing.

> I did notice another interesting case when looking at this. Fsck ends up
> in fsck_loose(), which has the sha1 and path of the loose object. It
> passes the sha1 to fsck_sha1(), and ignores the path entirely!
>
> So if you have a duplicate copy of the object in a pack, we'd actually
> find and check the duplicate. This can happen, e.g., if you had a loose
> object and fetched a thin-pack which made a copy of the loose object to
> complete the pack).
>
> Probably fsck_loose() should be more picky about making sure we are
> reading the data from the loose version we found.