Re: [PATCH] teach fast-export an --anonymize option

> Jeff King <peff@peff.net> writes:
> 
> > +/*
> > + * We anonymize each component of a path individually,
> > + * so that paths a/b and a/c will share a common root.
> > + * The paths are cached via anonymize_mem so that repeated
> > + * lookups for "a" will yield the same value.
> > + */
> > +static void anonymize_path(struct strbuf *out, const char *path,
> > +			   struct hashmap *map,
> > +			   char *(*generate)(const char *, size_t *))
> > +{
> > +	while (*path) {
> > +		const char *end_of_component = strchrnul(path, '/');
> > +		size_t len = end_of_component - path;
> > +		const char *c = anonymize_mem(map, generate, path, &len);
> > +		strbuf_add(out, c, len);
> > +		path = end_of_component;
> > +		if (*path)
> > +			strbuf_addch(out, *path++);
> > +	}
> > +}
> 
> Do two paths sort the same way before and after anonymisation?  For
> example, if generate() works as a simple substitution, it should map
> a character that sorts before (or after) '/' with another that also
> sorts before (or after) '/' for us to be able to diagnose an error
> that comes from D/F sort order confusion.