name-rev does not show the shortest path
- From
Uwe Kleine-König <ukleinek@informatik.uni-freiburg.de>
- Date
- Aug 23, 2007, 10:38 UTC
- Message-ID
- <20070823103817.GF6573@informatik.uni-freiburg.de>
Hello,
I want to check to which kernel version I need to upgrade to get a certain feature. For my case it was introduced in 0567a0c022d5b.
zeisberg@cassiopeia:~/gsrc/linux-2.6$ rev=0567a0c022d5b343370a343121f38fd89925de55
zeisberg@cassiopeia:~/gsrc/linux-2.6$ git name-rev --tags $rev 0567a0c022d5b343370a343121f38fd89925de55 tags/v2.6.22~1686^2~1^3~5
zeisberg@cassiopeia:~/gsrc/linux-2.6$ git name-rev --refs=*-rc1 $rev 0567a0c022d5b343370a343121f38fd89925de55 tags/v2.6.22-rc1~1009^2~1^3~5
I don't now the underlaying algorithm, maybe it's to get a short string?
Anyhow I want to know the earliest tag that includes this patch? Is there something I missed?
I remember there was a similar discussion regarding describe.
BTW: gitk does the right thing, it says:
Follows: v2.6.21-rc7 Precedes: v2.6.22-rc1
(called with
zeisberg@cassiopeia:~/gsrc/linux-2.6$ gitk 0567a0c022d5b343370a343121f38fd89925de55^..0567a0c022d5b343370a343121f38fd89925de55 )
I didn't check how it does that though.
Best regards Uwe
-- Uwe Kleine-König exit vi, lesson I: : q ! <CR>