Re: bsd group semantics
On Tue, Mar 31, 2009 at 08:55:00AM -0700, Junio C Hamano wrote:
> IIRC, DIR_HAS_BSD_GROUP_SEMANTICS means you do not have to ask explicitly
> with g+s to the filesystem to use the "subdirectory is owned by the same
> group as its parent" semantics. On SysV you have to ask; on BSD you do
> not have to (and do not need FORCE_DIR_SET_GID).
OK, I see. Thanks for the explanation. So the test is wrong, since it explicitly checks for g+s, and we only need it sometimes.
> That one was not about "you do not have to ask", but "you are not allowed
> to ask because the request will fail". Perhaps between FBSD4 and FBSD6
> things changed, and you can now make g+s request (which I presume is still
> a no-op other than setting the bit on)?
Yes, you can ask just fine now:
$ uname -sr
FreeBSD 6.1-RELEASE-p17-jc1
$ mkdir foo
$ ls -ld foo
drwxr-xr-x 2 peff peff 512 Mar 31 09:04 foo/
$ chmod g+s foo
$ ls -ld foo
drwxr-sr-x 2 peff peff 512 Mar 31 09:04 foo/
But it isn't necessary.
Show 5 quoted lines
> Ideally the test should be checking if the subdirectory is owned by the
> same group as the toplevel, but that is rather hard to correctly arrange,
> as it depends on the set of groups the user who runs the test belongs to,
> how the git work tree is set up (if it is owned by his primary group or a
> secondary), etc.
Shouldn't that just be:
perl -e 'sub group { return (stat(shift))[5] }' \
-e 'exit group($ARGV[0]) == group($ARGV[1]) ? 0 : 1' \
a b?
-Peff