Re: [RFC PATCH 1/1] for-each-ref: do not output empty lines
- From
Junio C Hamano <gitster@pobox.com>
- Date
- Sep 10, 2019, 06:14 UTC
- Message-ID
- <xmqqlfuwhe46.fsf@gitster-ct.c.googlers.com>
- In-Reply-To
- <xmqqpnk8heow.fsf@gitster-ct.c.googlers.com>
Junio C Hamano <gitster@pobox.com> writes:
Show 8 quoted lines
>> fwrite(final_buf.buf, 1, final_buf.len, stdout);
>> + if (final_buf.len)
>> + putchar('\n');
>
> While we are introducing a conditional, let's drop the useless
> fwrite of 0-byte while we are at it [*1*], i.e.
>
> if (final_buf.len && !omit_empty_lines) {Of course, that's a typo for "||"; if it is not empty, we'd emit no matter what, and if omit_empty is not given, we'd emit whether it is empty or not.
> fwrite(final_buf.buf, 1, final_buf.len, stdout);
> putchar('\n');
> }Show 14 quoted lines
>
> Thanks.
>
>
> [Footnote]
>
> *1* "While we are at it", the existing code tempts me to drop fwrite
> and replace it with something along the lines of...
>
> printf("%*s\n", count, buf)
>
> but I refrained from doing so. An enhancement patch like this
> is not a place to "improve" existing code (which should be done
> as a separate patch).