Re: [RFC/PATCH 0/2] Speed up fetch with large number of tags
- From
Julian Phillips <julian@quantumfyre.co.uk>
- Date
- Sep 16, 2009, 22:32 UTC
- Message-ID
- <alpine.LNX.2.00.0909162141140.13697@reaper.quantumfyre.co.uk>
- In-Reply-To
- <7vbplb2pi7.fsf@alter.siamese.dyndns.org>
On Wed, 16 Sep 2009, Junio C Hamano wrote:
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> Julian Phillips <julian@quantumfyre.co.uk> writes:
>
>> I have a repository at $dayjob where fetch was taking ~30s to tell me
>> that there were no updates.
>>
>> It turns out that I appear to have added a nasty linear search of all
>> remote refs for every commit (i.e. tag^{}) tag ref way back in the
>> original C implementation of fetch. This doesn't scale well to large
>> numbers of refs, so this replaces it with a hash table based lookup
>> instead, which brings the time down to a few seconds even for very large
>> ref counts.
>>
>> I haven't tested it with non-native transports, but there is no reason
>> to believe that the code should be transport specific.
>
> Very interesting.
>
> A few questions (not criticisms).
>
> * 1m50s to 4.5s is quite impressive, even if it is only in a repository
> with unusual refs-vs-commits ratio, but I personally think 10 refs per
> every commit is already on the borderline of being insane, and the
> normal ratio would be more like 1 refs per every 10-20 commits.I noticed the problem with a real repository at $dayjob, and did enough anaylsis to identiy the problem. I deliberately created a repository that should emphasise the problem so that it was easy to get a handle on.
Having applied the ref-dict patches fetch on my $dayjob repo has gone from ~30s to ~4.5s, which may not be as impressive - but is much easier to live with.
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> What are possible downsides with the new code in repositories with more > reasonable refs-vs-commits ratio? A hash table (with a sensible hash > function) would almost always outperform linear search in an randomly > ordered collection, so my gut tells me that there won't be performance > downsides, but are there other potential issues we should worry about?
I guess that main thing would be the extra memory usage.
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> * In an insanely large refs-vs-commits case, perhaps not 50000:1 but more > like 100:1, but with a history with far more than one commit, what is > the memory consumption? Judging from a cursory view, I think the way > ref-dict re-uses struct ref might be quite suboptimal, as you are using > only next (for hash-bucket link), old_sha1[] and its name field, and > also your ref_dict_add() calls alloc_ref() which calls one calloc() per > requested ref, instead of attempting any bulk allocation.
Yeah, I just reused struct for speed and convience of developing, to veryify that ref-dict would give me the speed I wanted. A final patch would want a more optimised version. Except that I've thrown the whole hash table thing away anyway.
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> * The outer loop is walking the list of refs from a transport, and the
> inner loop is walking a copy of the same list of refs from the same
> transport, looking for each refs/tags/X^{} what record, if any, existed
> for refs/tags/X.
>
> Would it make sense to further specialize your optimization? For
> example, something like...I actually arrived at somthing similar to this myself, after realising that I could use string_list as a basis.
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> * It is tempting to use a hash table when you have to deal with an > unordered collection, but in this case, wouldn't the refs obtained from > the transport (it's essentially a ls-remote output, isn't it?) be > sorted? Can't you take advantage of that fact to optimize the loop, > without adding a specialized hash table implementation?
I wasn't sure if we could rely on the refs list being sorted. But I've got a new version that uses an extra string_list instead that is actually slightly faster. I'll post that shortly.
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> We find refs/tags/v0.99 immediately followed by refs/tags/v0.99^{} in
> the ls-remote output. And the inefficient loop is about finding
> refs/tags/v0.99 when we see refs/tags/v0.99^{}, so if we remember the
> tag ref we saw in the previous round, we can check with that first to
> make sure our "sorted" assumption holds true, and optimize the loop out
> that way, no?-- Julian --- Bilbo's First Law: You cannot count friends that are all packed up in barrels.