Re: [PATCH] run-command: don't spam trace2_child_exit()
- From
Josh Steadmon <steadmon@google.com>
- Date
- May 5, 2022, 19:44 UTC
- Message-ID
- <YnQpFwcB3V07qNi3@google.com>
- In-Reply-To
- <xmqqr15gev94.fsf@gitster.g>
On 2022.04.28 14:46, Junio C Hamano wrote:
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> Josh Steadmon <steadmon@google.com> writes: > > > In rare cases, wait_or_whine() cannot determine a child process's exit > > status (and will return -1 in this case). This can cause Git to issue > > trace2 child_exit events despite the fact that the child is still > > running. > > Rather, we do not even know if the child is still running when it > happens, right?
Correct, if you'd like me to clarify the commit message I'll send a V2.
> It is curious what "rare cases" makes the symptom > appear. Do we know?
Unfortunately, no. The quoted 80 million exit event instance was not reproducible.
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> The patch looks OK from the "we do not know the child exited in this > case, so we shouldn't be reporting the child exit" point of view, of > course. Having one event that started a child in the log and then > having millions of events that reports the exit of the (same) child > is way too broken. With this change, we remove these phoney exit > events from the log. > > Do we know, for such a child process that caused these millions > phoney exit events, we got a real exit event at the end?
We don't know. The trace log filled up the user's disk in this case, so the log was truncated.
Show 5 quoted lines
> Otherwise, > we'd still have a similar problem in the opposite direction, i.e. a > child has a start event recorded, many exit event discarded but the > log lacks the true exit event for the child, implying that the child > is still running because we failed to log its exit?
Yes, that is a weakness with this approach.
Show 10 quoted lines
> > int finish_command_in_signal(struct child_process *cmd)
> > {
> > int ret = wait_or_whine(cmd->pid, cmd->args.v[0], 1);
> > - trace2_child_exit(cmd, ret);
> > + if (ret != -1)
> > + trace2_child_exit(cmd, ret);
> > return ret;
> > }
>
> Will queue; thanks.Thanks, and sorry for the delayed reply, I've been out sick for a few days.