RE: Git checkout multiple options issue

From: COLLOMB Joris -EXT <joris.collomb-ext@alstomgroup.com>
Date: Jan 28, 2019, 14:24 UTC
Message-ID: <HE1PR01MB3722D90668E75E4BCDBA71F2A9960@HE1PR01MB3722.eurprd01.prod.exchangelabs.com>
In-Reply-To: <000201d4b713$7edcd3d0$7c967b70$@nexbridge.com>

Thanks for answer,

git checkout -f -b "branch_name" gives me " Fatal: A branch named 'branch_name' already exists."

I understand that here the checkout is force, but not the branch creation. The opposite option order doesn't work:

git checkout -b -f "branch_name" gives me "Fatal: '-f' is not a valid branch name."

Once again sorry if this is expected behavior.

[For clarity, I'm trying to move a branch and checkout it with one command.]

Regards, Joris

-----Message d'origine----- De : Randall S. Becker <rsbecker@nexbridge.com> Envoyé : lundi 28 janvier 2019 15:12 À : COLLOMB Joris -EXT <joris.collomb-ext@alstomgroup.com>; git@vger.kernel.org Objet : RE: Git checkout multiple options issue

On January 28, 2019 8:25, COLLOMB Joris wrote:

Show 6 quoted lines

> git checkout -fb "branch_name"
> (force branch creation and checkout it)
>
> doesn't work (even if option a separated).
>
> I don't know if this is consider as an issue, but here it is.

I think you might mean (which works on every platform I have):

git checkout -f -b "branch_name"

There is no provision for aggregating options into one. -fb (invalid) is not the same as -f -b (valid).

Regards, Randall

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