Re: [BUG] Failed to sign commit

From: pedro rijo <pedrorijo91@gmail.com>
Date: Jun 7, 2017, 10:39 UTC
Message-ID: <CAPMsMoCi4JRB7e6DLLOx+i-Gbfeh=EXeytWPn0WruOPJQZ0vow@mail.gmail.com>
In-Reply-To: <20170607103326.GB27719@alpha.vpn.ikke.info>

Thanks for the hint!

$ GIT_TRACE=1 git commit --allow-empty -v -m "lol" 11:37:24.594795 git.c:369 trace: built-in: git 'commit' '--allow-empty' '-v' '-m' 'lol' 11:37:24.605842 run-command.c:369 trace: run_command: 'gpg' '--status-fd=2' '-bsau' '8AEC0DB537A9FC7E' error: gpg failed to sign the data fatal: failed to write commit object

It seems more a gpg problem no? something not well configured after the update perhaps?

2017-06-07 11:33 GMT+01:00 Kevin Daudt <me@ikke.info>:

Show 26 quoted lines

> On Wed, Jun 07, 2017 at 10:46:08AM +0100, pedro rijo wrote:
>> Recently I've updated a bunch of stuff, including git and gpg. I'm using
>>
>> - mac OS 10.10.5
>> - git 2.13.1
>> - gpg (GnuPG) 2.1.21 / libgcrypt 1.7.7
>>
>> When I do
>>
>> $ git commit --allow-empty -v -m "lol"
>> error: gpg failed to sign the data
>> fatal: failed to write commit object
>>
>> I tried the verbose flag hoping to have a better insight, but not very
>> useful. Not sure if it's a gpg problem, a git problem, or something
>> else.
>>
>> Any clue on how to debug the problem? Do you need any gpg output to
>> better understand the problem?
>>
>> Thanks,
>> Pedro
>
> GIT_TRACE=1 git commit --allow-empty -v -m "lol" might give some extra
> feedback (ie, what gpg command git runs), and try to see if you can
> replicate it.

-- 
Obrigado,

Pedro Rijo