Re: [PATCH] regex: do not call `regfree()` if compilation fails

> On Mon, May 21, 2018 at 2:43 PM, Stefan Beller <sbeller@google.com> wrote:
>> On Sun, May 20, 2018 at 3:50 AM, Martin Ågren <martin.agren@gmail.com> wrote:
>>> It is apparently undefined behavior to call `regfree()` on a regex where
>>> `regcomp()` failed. [...]
>>>
>>> diff --git a/diffcore-pickaxe.c b/diffcore-pickaxe.c
>>> @@ -215,7 +215,6 @@ static void regcomp_or_die(regex_t *regex, const char *needle, int cflags)
>>>                 /* The POSIX.2 people are surely sick */
>>>                 char errbuf[1024];
>>>                 regerror(err, regex, errbuf, 1024);
>>> -               regfree(regex);
>>>                 die("invalid regex: %s", errbuf);
>>
>> While the commit message is very clear why we supposedly introduce a leak here,
>> it is hard to be found from the source code (as we only delete code
>> there, so digging
>> for history is not obvious), so maybe
>>
>>      /* regfree(regex) is invalid here */
>>
>> instead?
>
> The commit message doesn't say that we are supposedly introducing a
> leak (and, indeed, no resources should have been allocated to the
> 'regex' upon failed compile). It's saying that removing this call
> potentially avoids a crash under some implementations.
>
> Given that the very next line is die(), and that the function name has
> "_or_die" in it, I'm not sure that an in-code comment about regfree()
> being invalid upon failed compile would be all that helpful; indeed,
> it could be confusing, causing the reader to wonder why that is
> significant if we're just dying anyhow. I find that the patch, as is,
> clarifies rather than muddles the situation.