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Re: [PATCH] remote: handle negative refspecs in git remote show

From
Jacob Keller <jacob.keller@gmail.com>
Date
Jun 16, 2022, 20:41 UTC
Message-ID
<CA+P7+xpS0v9Oi3t4S76AcNRazdzJEEj6HxzO+z+dAFDPJ=yHJA@mail.gmail.com>
In-Reply-To
<xmqqzgidy52c.fsf@gitster.g>
On Wed, Jun 15, 2022 at 2:45 PM Junio C Hamano <gitster@pobox.com> wrote:
Show 57 quoted lines
>
> Jacob Keller <jacob.keller@gmail.com> writes:
>
> > Fix this by checking negative refspecs inside of get_ref_states. For
> > each ref which matches a negative refspec, copy it into a "skipped" list
> > and remove it from the fetch map. This allows us to show the following
> > output instead:
> >
> >   * remote jdk19
> >     Fetch URL: git@github.com:openjdk/jdk19.git
> >     Push  URL: git@github.com:openjdk/jdk19.git
> >     HEAD branch: master
> >     Remote branches:
> >       master tracked
> >       pr/1   skipped
> >       pr/2   skipped
> >       pr/3   skipped
> >     Local ref configured for 'git push':
> >       master pushes to master (fast-forwardable)
> >
> > By showing the refs as skipped, it helps clarify that these references
> > won't actually be fetched. Alternatively, we could simply remove them
> > entirely.
>
> Very sensible.
>
> > @@ -367,6 +368,24 @@ static int get_ref_states(const struct ref *remote_refs, struct ref_states *stat
> >                       die(_("Could not get fetch map for refspec %s"),
> >                               states->remote->fetch.raw[i]);
> >
> > +     /* handle negative refspecs first */
> > +     for (tail = &fetch_map; *tail; ) {
> > +             ref = *tail;
> > +
> > +             if (omit_name_by_refspec(ref->name, &states->remote->fetch)) {
> > +                     string_list_append(&states->skipped, abbrev_branch(ref->name));
> > +
> > +                     /* Matched a negative refspec, so remove this ref from
> > +                      * consideration for being a new or tracked ref.
> > +                      */
> > +                     *tail = ref->next;
> > +                     free(ref->peer_ref);
> > +                     free(ref);
> > +             } else {
> > +                     tail = &ref->next;
> > +             }
> > +     }
>
>
> This is somewhat curious.  Do we really need to destroy the
> fetch_map like the above?  I know by removing skipped items from the
> list, the existing loop (below) can stop having to worry about them,
> but the caller of get_ref_states() may later want to iterate over
> the full fetch_map for other reasons (even if the current one does
> not, a future version of the caller may have a reason to do so that
> we do not know right now yet).
>

Good point. I'll fix this. I think we can just move the omit_name_by_refspec into the other loop.

Show 7 quoted lines
> > +
> >       for (ref = fetch_map; ref; ref = ref->next) {
> >               if (!ref->peer_ref || !ref_exists(ref->peer_ref->name))
> >                       string_list_append(&states->new_refs, abbrev_branch(ref->name));
>
> IOW, is adding a new condition to this existing loop insufficient?
>

The tricky part here is that we don't have a simple check, and we're currently iterating over all of the refspecs each time. But we have to do that regardless so I think this makes sense. Will fix.

Show 12 quoted lines
>         for (ref = fetch_map; ref; ref = ref->next) {
> -               if (!ref->peer_ref || !ref_exists(ref->peer_ref->name))
> +               if (omit_name_by_refspec(ref->name, &states->remote->fetch))
> +                       string_list_append(&states->skipped, abbrev_branch(ref->name));
> +               else if (!ref->peer_ref || !ref_exists(ref->peer_ref->name))
>                         string_list_append(&states->new_refs, abbrev_branch(ref->name));
>                 else
>                         string_list_append(&states->tracked, abbrev_branch(ref->name));
>         }
>
>
> Thanks.
Previous: Junio C HamanoNext: Junio C Hamano
Message 8 of 11 in “remote: handle negative refspecs in git remote show”
  1. remote: handle negative refspecs in git remote showJacob Keller, Jun 14, 2022
  2. Taylor BlauJun 14, 2022
  3. Jacob KellerJun 14, 2022
  4. Taylor BlauJun 14, 2022
  5. Jacob KellerJun 16, 2022
  6. Jacob KellerJun 14, 2022
  7. Junio C HamanoJun 15, 2022
  8. Jacob KellerJun 16, 2022
  9. Junio C HamanoJun 16, 2022
  10. Jacob KellerJun 16, 2022
  11. Jacob KellerJun 16, 2022

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