Re: how to squash two commits into only one
- From
- Lynn Lin <lynn.xin.lin@gmail.com>
- Date
- Mar 29, 2011, 08:24 UTC
- Message-ID
- <AANLkTin-0cBa293CQSf4kwMUG=w2j5zkSz1oBDhNqaNe@mail.gmail.com>
- In-Reply-To
- <AANLkTi=5e4WUuZHcEJD50yJTw2eyYN_dN1S_7z62qy88@mail.gmail.com>
On Tue, Mar 29, 2011 at 2:15 PM, Tor Arntsen <tor@spacetec.no> wrote:
Show 29 quoted lines
> On Tue, Mar 29, 2011 at 07:42, Lynn Lin <lynn.xin.lin@gmail.com> wrote: >> All, >> I have only have two commits in repo,then I want to squash these >> two commit into one through git rebase -i .However it fails >> >> $ git rebase -i HEAD^1 >> it only show up one commit so can't squash (can't squash without a >> previous commit) > > To squash commits with rebase -i: > git log > (identify the commit you wish to squash to) > git rebase -i <the commit _before_ the one you want to squash to) > > e.g. > git log > 1 > 2 > 3 > 4 > .. > you want to squash 2 into 3: Use git rebase -i 4 > (4 is really a hash of course). > > HEAD^some-value is OK sometimes but when I want to fix stuff down in > the commit chain somewhere I find it simpler to use the hashes - just > mark and paste. > Anyway the real point is that with rebase -i you must specify the last > commit _before_ the range you want to work with.
Thanks .However my case is like: git log 1 2
I want to squash 1 to 2,what's the commit I should specify with rebase -i
> -Tor >