Re: how to list commits on branch since last merge

From: Jay Soffian <jaysoffian@gmail.com>
Date: Mar 8, 2011, 17:39 UTC
Message-ID: <AANLkTimE52XWMtpuyaU7MbnyYVszKqNbTPSV=QxLyij3@mail.gmail.com>
In-Reply-To: <20110308171251.GA1823@sigill.intra.peff.net>

On Tue, Mar 8, 2011 at 12:12 PM, Jeff King <peff@peff.net> wrote:

Show 12 quoted lines

> On Tue, Mar 08, 2011 at 05:11:16AM -0500, Jay Soffian wrote:
>
>> Going back to my original picture, I mean commit m:
>>
>>   o---o---x---o---...    foo
>>    \       \
>>     o---o---m---o---...  bar
>>
>> merge-base foo bar gives me x; to get m I then need to grep the output
>> of rev-list --parents for x.
>
> Isn't the merge the first commit in bar that is not in foo? IOW:

No, because bar is never merged to foo. Let me relabel the picture:

   o---o---x---o---...    foo
    \       \
     a---b---c---d---...  bar

>  git rev-list foo..bar | tail -n 1

That would return 'a'. merge-base foo bar returns x. I want 'c'. So again, I can do either:

  $ git rev-list foo bar --merges --parents | grep " $(git merge-base foo bar)"

Or:

  $ git rev-list --ancestry-path foo...bar ^foo | tail -n 1

I guess this is not at all a common thing, since it seems to be confounding the list. :-)

My use case is that I maintain a downstream project, so bar never merges back to foo, but sometimes I ask the question "what have we done on bar since we last merged in foo". I think --ancestry-path really is the answer:

  $ git log --reverse --ancestry-path foo...bar ^foo

Is actually quite nice.

j.