Re: Distribution of longest common hash prefixes
- From
Randal L. Schwartz <merlyn@stonehenge.com>
- Date
- Apr 2, 2007, 17:33 UTC
- Message-ID
- <86r6r2isva.fsf@blue.stonehenge.com>
- In-Reply-To
- <86y7laitlz.fsf@blue.stonehenge.com>
>>>>> "Randal" == Randal L Schwartz <merlyn@stonehenge.com> writes:
Randal> git-rev-list --objects HEAD | sort | perl -lne ' Randal> substr($_, 40) = ""; Randal> if (defined $p) { Randal> ($p ^ $_) =~ /^(\0*)/; Randal> $common = length $1; Randal> if (defined $pcommon) { Randal> $count[$pcommon > $common ? $pcommon : $common]++; Randal> } Randal> } Randal> $p = $_; Randal> $pcommon = $common; Randal> END { print "$_: $count[$_]" for 0..$#count } Randal> '
And that's off by one on either end. :)
git-rev-list --objects HEAD | sort | perl -lne '
substr($_, 40) = "";
if (defined $p) {
($p ^ $_) =~ /^(\0*)/;
$common = length $1;
if (defined $pcommon) {
$count[$pcommon > $common ? $pcommon : $common]++;
} else {
$count[$common]++; # first item
}
}
$p = $_;
$pcommon = $common;
END {
$count[$common]++; # last item
print "$_: $count[$_]" for 0..$#count;
}
'Which now yields:
0:
1:
2: 6
3: 21155
4: 15008
5: 1232
6: 90
7:
8: 2And *that* totals to 37493, which is the number of objects. Yeay.
-- Randal L. Schwartz - Stonehenge Consulting Services, Inc. - +1 503 777 0095 <merlyn@stonehenge.com> <URL:http://www.stonehenge.com/merlyn/> Perl/Unix/security consulting, Technical writing, Comedy, etc. etc. See PerlTraining.Stonehenge.com for onsite and open-enrollment Perl training!