[PATCH] checkout-cache -a should not extract unmerged stages
- From
Junio C Hamano <junkio@cox.net>
- Date
- Apr 17, 2005, 05:30 UTC
- Message-ID
- <7vy8bi0y2k.fsf@assigned-by-dhcp.cox.net>
When checkout-cache -a is run, currently it attempts to extract each existing unmerged stage to the same destination and complains to what it itself has done. This is nonsensical.
Presumably, the user is running checkout-cache -a in order to verify the result of the part that has cleanly been merged. So check out only stage 0 entries and give warnings for paths that are unmerged.
Signed-off-by: Junio C Hamano <junkio@cox.net> ---
checkout-cache.c | 11 +++++++++++ 1 files changed, 11 insertions(+)
checkout-cache.c: 431b7032576f40d93a08be801e26f76c168ed57b --- checkout-cache.c +++ checkout-cache.c 2005-04-16 22:23:15.000000000 -0700
@@ -121,10 +121,21 @@ static int checkout_all(void) { + struct cache_entry *unmerge_skipping = NULL; int i; for (i = 0; i < active_nr ; i++) { struct cache_entry *ce = active_cache[i]; + if (ce_stage(ce)) { + if (!unmerge_skipping || + strcmp(unmerge_skipping->name, ce->name)) + fprintf(stderr, + "checkout-cache: needs merge %s\n", + ce->name); + unmerge_skipping = ce; + continue; + } + unmerge_skipping = NULL; if (checkout_entry(ce) < 0) return -1; }