Re: t0005-signals.sh fails with ksh

From: evgeny <illumsoft.org@gmail.com>
Date: May 8, 2015, 23:05 UTC
Message-ID: <727591966.20150509020506@gmail.com>
In-Reply-To: <xmqq1tiqkdue.fsf@gitster.dls.corp.google.com>

Hello Junio,

Friday, May 8, 2015, 11:34:49 PM, you wrote:

> evgeny <illumsoft.org@gmail.com> writes:

Show 6 quoted lines

>> expecting success: 
>>         OUT=$( ((large_git; echo $? 1>&3) | :) 3>&1 ) &&
>>         test "$OUT" -eq 141
>>
>> t0005-signals.sh[499]: eval: syntax error at line 4: `(' unmatched
>> Memory fault

> Does this work if you did

>         OUT=$( ( (large_git ; echo $? 1>&3) | : ) 3>&2 ) &&

> instead?

Yes. when I add a space between parentheses and change 141 to 269 all tests in t0005-signals.sh are passed.

... stripped first lines ... ok 3 - create blob

expecting success: 
        OUT=$( ( (large_git; echo $? 1>&3) | :) 3>&1 ) &&
        test "$OUT" -eq 269

ok 4 - a constipated git dies with SIGPIPE

expecting success: 
        OUT=$( ( (trap "" PIPE; large_git; echo $? 1>&3) | :) 3>&1 ) &&
        test "$OUT" -eq 269

ok 5 - a constipated git dies with SIGPIPE even if parent ignores it

# passed all 5 test(s) 1..5

Show 6 quoted lines

>> 'man ksh' reads:
>>   (list)
>>     Execute  list  in  a  separate environment.
>>     Note, that if two adjacent open parentheses are needed for nesting,
>>     a space must be inserted to avoid evaluation as an arithmetic command as
>>     described above.

> Hmm, I cannot see "as described above" in your message, but isn't
> that talking about a common mistake of turning cmd1 in this pipeline

>         x=$(cmd1 | cmd2)

> into a series of two commands, e.g. (cmd1a && cmd1b) and saying

>         x=$((cmd1a && cmd1b) | cmd2)

> which does make "$((" interpreted as the beginning of arithmetic
> expansion?

> And the "OUT=$( ((large..." construct seems to be written in order
> to avoid that exact issue (notice the SP after "$(").

> Puzzled....

It was an excerpt from ksh's man page, and "as described above" refers to previous paragraph where "((expression))" expained.

I think the space after "$(" refers to "Arithmetic Substitution" paragraph and the following two parentheses are about "Note, that if two adjacent open parentheses are needed for nesting, a space must be inserted"

              
$ man ksh
... skipped ...

      Arithmetic Substitution.
       An  arithmetic  expression  enclosed  in  double parentheses preceded by a dollar sign ( $(()) ) is replaced by the
       value of the arithmetic expression within the double parentheses.

... skipped ...

       ((expression))
              The expression is evaluated using the rules for arithmetic evaluation described below.  If the value of  the
              arithmetic expression is non-zero, the exit status is 0, otherwise the exit status is 1.

       (list)
              Execute list in a separate environment.  Note, that if two adjacent open parentheses are needed for nesting,
              a space must be inserted to avoid evaluation as an arithmetic command as described above.

... skipped ...

Some info about my system:

$ head -1 /etc/os-release PRETTY_NAME="Debian GNU/Linux 7 (wheezy)"

$ ksh --version
  version         sh (AT&T Research) 93u+ 2012-02-29

  It is surprise for me that ksh is so old.
  
$ ls -l $(which ksh)
lrwxrwxrwx 1 root root 29 May  6 22:44 /usr/bin/ksh -> /etc/alternatives/usr.bin.ksh

$ ls -l /etc/alternatives/usr.bin.ksh lrwxrwxrwx 1 root root 10 May 6 22:44 /etc/alternatives/usr.bin.ksh -> /bin/ksh93

$ ls -l /bin/ksh93
-rwxr-xr-x 1 root root 1446836 Jan  3  2013 /bin/ksh93

-- 
Best regards,
 evgeny