Re: Concurrent pushes updating the same ref
- From
Marc Branchaud <marcnarc@xiplink.com>
- Date
- Jan 6, 2011, 21:51 UTC
- Message-ID
- <4D263979.1080403@xiplink.com>
- In-Reply-To
- <7v1v4pbz6y.fsf@alter.siamese.dyndns.org>
On 11-01-06 02:37 PM, Junio C Hamano wrote:
Show 31 quoted lines
> Jeff King <peff@peff.net> writes: > >> On Thu, Jan 06, 2011 at 10:46:38AM -0500, Marc Branchaud wrote: >> >>> fatal: Unable to create >>> '/usr/xiplink/git/public/Main.git/refs/builds/3.3.0-3.lock': File exists. >>> If no other git process is currently running, this probably means a >>> git process crashed in this repository earlier. Make sure no other git >>> process is running and remove the file manually to continue. >>> fatal: The remote end hung up unexpectedly >>> >>> I think the cause is pretty obvious, and in a normal interactive situation >>> the solution would be to simply try again. But in a script trying again >>> isn't so straightforward. >>> >>> So I'm wondering if there's any sense or desire to make git a little more >>> flexible here. Maybe teach it to wait and try again once or twice when it >>> sees a lock file. I presume that normally a ref lock file should disappear >>> pretty quickly, so there shouldn't be a need to wait very long. >> >> Yeah, we probably should try again. The simplest possible (and untested) >> patch is below. However, a few caveats: >> >> 1. This patch unconditionally retries for all lock files. Do all >> callers want that? > > I actually have to say that _no_ caller should want this. If somebody > earlier crashed, we would want to know about it (and how). If somebody > else alive is actively holding a lock, why not make it the responsibility > of a calling script to decide if it wants to retry itself or perhaps > decide to do something else?
I'm not sure I follow this.
How would retrying a few times prevent us from finding out about an earlier crash? It's not like we're overriding the lock by retrying. Nobody's going to be able to remove a lock created by a crashed process, right?
And if someone active doesn't release the lock and the low-level code retried a few times, the caller can still decide what to do. I don't see how it would even impact that decision -- if the caller wants to try again, the system can still retry a few times underneath the caller's one retry. It seems fine to me.
M.