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URL-escape the '@' sign in username/password

From
GCGabriel Corona <gabriel.corona@enst-bretagne.fr>
Date
Nov 10, 2010, 01:33 UTC
Message-ID
<4CD9F655.8030908@enst-bretagne.fr>
Hello,

I've been trying to use git with a http/webdav repository with an username containing a '@' character (foobar@host). The git FAQ [1] suggests escaping the '@' character with percent encoding. However, the username and password of the URI are not unescaped and the username foobar%400host is sent to the web server.

$ #Launch a dummy web server $ webfsd -4 -r ~/bidouilles/temp/empty/ -L- -F -bfoobar@host:secret -p8000 -i 127.0.0.1 &

$ git clone http://foobar%40host:secret@127.0.0.1:8000/ Cloning into 8000... fatal: Authentication failed

Compare with:
$ git clone http://127.0.0.1:8000/
Cloning into 8000...
Username: foobar@host
Password: secret
fatal: http://127.0.0.1:8000/info/refs not found: did you run git 
update-server-info on the server?

[1] https://git.wiki.kernel.org/index.php/GitFaq#My_username_contains_a_.27.40.27.2C_I_can.27t_clone_through_HTTP.2FHTTPS

diff --git a/http.c b/http.c
index 0a5011f..c4d18a9 100644
--- a/http.c
+++ b/http.c
@@ -297,7 +297,7 @@ static CURL *get_curl_handle(void)

  static void http_auth_init(const char *url)
  {
-       char *at, *colon, *cp, *slash;
+       char *at, *colon, *cp, *slash, *temp;
         int len;

         cp = strstr(url, "://");
@@ -322,16 +322,25 @@ static void http_auth_init(const char *url)
                 user_name = xmalloc(len + 1);
                 memcpy(user_name, cp, len);
                 user_name[len] = '\0';
+               temp = url_decode(user_name);
+               free(user_name);
+               user_name = temp;
                 user_pass = NULL;
         } else {
                 len = colon - cp;
                 user_name = xmalloc(len + 1);
                 memcpy(user_name, cp, len);
                 user_name[len] = '\0';
+               temp = url_decode(user_name);
+               free(user_name);
+               user_name = temp;
                 len = at - (colon + 1);
                 user_pass = xmalloc(len + 1);
                 memcpy(user_pass, colon + 1, len);
                 user_pass[len] = '\0';
+               temp = url_decode(user_pass);
+               free(user_pass);
+               user_pass = temp;
         }
  }
-- 
Gabriel
Next: Matthieu Moy
Message 1 of 2 in “URL-escape the '@' sign in username/password”
  1. Gabriel CoronaNov 10, 2010
  2. Matthieu MoyNov 10, 2010

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