Re: [RFC] notes: avoid recommitting identical trees
- From
Michael J Gruber <git@drmicha.warpmail.net>
- Date
- Aug 31, 2010, 18:45 UTC
- Message-ID
- <4C7D4DC2.4070008@drmicha.warpmail.net>
- In-Reply-To
- <20100831182931.GA21489@sigill.intra.peff.net>
Jeff King venit, vidit, dixit 31.08.2010 20:29:
Show 31 quoted lines
> On Tue, Aug 31, 2010 at 08:26:34PM +0200, Michael J Gruber wrote:
>
>> Junio C Hamano venit, vidit, dixit 31.08.2010 18:44:
>>> Michael J Gruber <git@drmicha.warpmail.net> writes:
>>>
>>>>>> + if (!parent || parse_commit(parent->item) || parse_tree(parent->item->tree) ||
>>>>>> + hashcmp(parent->item->tree->object.sha1, tree_sha1)) {
>>>>>
>>>>> I didn't check, but I can imagine you can drop the parse_tree here. We
>>>>> should know the object sha1 once the commit is parsed.
>>>>
>>>> parse_commit() does a lookup_tree() but I don't think that it parses the
>>>> tree, i.e. I don't hink it fills in tree->object.sha1.
>>>
>>> Huh? parse_tree(tree) calls read_sha1_file(tree->object.sha1) to parse
>>> the tree. How can it do without filling tree->object.sha1?
>>>
>>
>> Sure parse_tree() does that. That's why I call it. I never claimed it
>> doesn't.
>
> I think the claim is that it is already parsed. Look at parse_tree. The
> first non-declaration lines are:
>
> if (item->object.parsed)
> return 0;
> buffer = read_sha1_file(item->object.sha1, &type, &size);
>
> So _somebody_ has already filled in item->object.sha1.
>
> -PeffOK, now I understand Junio's answer... ...and I also see where lookup_tree() fills the sha1, which I failed to see before.
I guess what happened was that I had the parse_tree without parse_commit, which segfaulted, and then inserted parse_commit.
In any case, it seems Johan is going with his approach, so you can forget about the RFC, be it with or without parse_tree.
Michael