Is there something like a git format-patch --squash?

From: Avery Pennarun <apenwarr@gmail.com>
Date: Feb 18, 2010, 19:45 UTC
Message-ID: <32541b131002181145w44d69e9eo150d08f34273cefb@mail.gmail.com>

On Thu, Feb 18, 2010 at 1:38 PM, Avery Pennarun <apenwarr@gmail.com> wrote:

Show 19 quoted lines

> On Thu, Feb 18, 2010 at 12:11 AM, Jeff King <peff@peff.net> wrote:
>> One simple strategy would be to squash all side-branch development into
>> a single commit.
>
> Something like this (replace MY_START_BRANCH with your starting
> branch, and do this in a clone of your repository so you don't destroy
> anything by accident):
>
>        parent=""
>        git rev-list --first-parent --reverse  | while read commit; do
>                if [ -z "$parent" ]; then
>                        git checkout -f $commit
>                        git clean -fdx
>                else
>                        git diff $parent $commit | git apply --index
>                        git commit -C $commit
>                fi
>                parent=$commit
>        done

In the above, in the 'else' clause, what I really wanted was something like:

   git format-patch --stdout --squash $parent..$commit

with one big "| git am" at the end of the loop.

However, format-patch seems to have no way of just producing a single patch with all the changes from a particular branch. Is there some other easy command that would do what I want? It seems like something that someone would have wanted before now.

Thanks,

Avery