Re: [PATCH 2/2] strbuf: allow to use preallocated memory

> William <william.duclot@ensimag.grenoble-inp.fr> writes:
> 
> > On Mon, May 30, 2016 at 11:34:42PM -0700, Junio C Hamano wrote:
> >
> >> As long as your "on stack strbuf" allows lengthening the string
> >> beyond the initial allocation (i.e. .alloc, not .len), the user of
> >> the API (i.e. the one that placed the strbuf on its stack) would not
> >> know when the implementation (i.e. the code in this patch) decides
> >> to switch to allocated memory, so it must call strbuf_release()
> >> before it leaves.  Which in turn means that your implementation of
> >> strbuf_release() must be prepared to be take a strbuf that still has
> >> its string on the stack.
> >
> > Well, my implementation does handle a strbuf that still has its
> > string on the stack: the buffer won't be freed in this case (only a
> > reset to STRBUF_INIT).
> > Unless I misunderstood you?
> 
> I think Junio meant:
> 
> void f()
> {
> 	struct strbuf sb;
> 	char buf[N];
> 	strbuf_wrap_preallocated(&sb, buf, ...);
> 	strbuf_add(&sb, ...);
> 
> 	// is it safe to just let sb reach the end of its scope?
> }
> 
> To answer the last question, the user would need to know too much about
> the allocation policy, so in this case the user should call
> strbuf_release(), and let it chose whether to call "free()"
> (OWNS_MEMORY) or not. This is OK with your implementation, but the doc
> needs to reflect this.