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Re: [PATCH] Makefile: do not compile git with debugging symbols by default

From
Mike Hommey <mh@glandium.org>
Date
Jan 22, 2015, 22:55 UTC
Message-ID
<20150122225517.GB31912@glandium.org>
In-Reply-To
<20150122183538.GA20085@peff.net>
On Thu, Jan 22, 2015 at 01:35:38PM -0500, Jeff King wrote:
Show 10 quoted lines
> On Thu, Jan 22, 2015 at 06:36:41PM +0100, Matthieu Moy wrote:
> 
> > > Yes, main point is size of executable.
> > 
> > The Git executable is a few megabytes, i.e. 0.001% the size of a really
> > small hard disk. The benefit seems really negligible to me.
> 
> I don't know the layout of the symbols with respect to the code, or
> whether the stripped version might reduce memory pressure. So in theory
> it could have a performance impact.

It doesn't. Debugging info is in a part of the file that is not mapped in memory, and in a part that can be removed without affecting the rest of the file, so it's more or less at the end.

Mike
Previous: Jeff KingNext: David Aguilar
Message 8 of 9 in “Makefile: do not compile git with debugging symbols by default”
  1. Makefile: do not compile git with debugging symbols by defaultAlexander Kuleshov, Jan 22, 2015
  2. Jeff KingJan 22, 2015
  3. Mike HommeyJan 22, 2015
  4. Alexander KuleshovJan 22, 2015
  5. Alexander KuleshovJan 22, 2015
  6. Matthieu MoyJan 22, 2015
  7. Jeff KingJan 22, 2015
  8. Mike HommeyJan 22, 2015
  9. David AguilarJan 27, 2015

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