Re: Status after 'git clone --no-checkout' ?
- From
Jeff King <peff@peff.net>
- Date
- Dec 1, 2011, 19:00 UTC
- Message-ID
- <20111201190058.GC2873@sigill.intra.peff.net>
- In-Reply-To
- <jb59h0$p3e$1@dough.gmane.org>
On Wed, Nov 30, 2011 at 02:02:22PM +0100, norbert.nemec wrote:
> what exactly is the status after 'git clone --no-checkout'? Is there > any straightforward way how one could end up in this state starting > from a regularly checked out repository?
You have a HEAD which points to some actual commit, but no index or working tree. I don't think there is a particular name for this state.
You can get something similar in an existing repo by deleting all of the working tree files and removing .git/index.
> 'git checkout' without any further options serves to move from the > aforementioned special state to a regular checked out state. > Otherwise it never seems to do anything. Are there any other > situations where 'git checkout' on its own would have any effect?
By itself, I don't think so. But you can use "git checkout -f" to discard changes in the index and working tree, setting them back to the state in HEAD.
At one point, some people used "git checkout" as a no-op, because it would print the "ahead/behind" information with respect to the upstream. These days, that information is part of "git status", so I suspect people use that instead.
-Peff