Re: WIP: asciidoc replacement
- From
Jeff King <peff@peff.net>
- Date
- Oct 3, 2007, 04:51 UTC
- Message-ID
- <20071003045148.GD11905@coredump.intra.peff.net>
- In-Reply-To
- <Pine.LNX.4.64.0710030506360.28395@racer.site>
On Wed, Oct 03, 2007 at 05:23:35AM +0100, Johannes Schindelin wrote:
Show 5 quoted lines
> > > #!/usr/bin/perl > > > > Add -w for warnings, also use strict; > > <dumb>What does "use strict;" imply?</dumb>
Try "perldoc strict" for details.
Show 9 quoted lines
> > > if ($par =~ /^\. /s) {
> > > my @lines = split(/^\. /m, $par);
> > > shift @lines;
> > > $conv->enumeration(\@lines);
> > > } elsif ($par =~ /^\* /s) {
> >
> > uncuddle your elsif's;
>
> I'm sorry... What do you mean?I think he means reformatting to
if (condition) {
}
elsif (condition) {
}Show 5 quoted lines
> > $result = ( $par =~ /^\. /s ? $conv->do_enum($par) : > > $par =~ /^\[verse\]/ ? $conv->do_verse($par) : > > ... ) > > I do not like that way... is it Perl standard to code like that?
It's quite common if you have a dispatch function, but obviously not required.
Show 14 quoted lines
> > > $title =~ s/\(\d+\)$//;
> > > print '.\" Title: ' . $title
> > > . '.\" Author: ' . "\n"
> > > . '.\" Generator: ' . $self->{generator} . "\n"
> > > . '.\" Date: ' . $self->{date} . "\n"
> > > . '.\" Manual: ' . $self->{manual} . "\n"
> > > . '.\" Source: ' . $self->{git_version} . "\n"
> > > . '.\"' . "\n";
> > > }
> >
> > I'd consider a HERE-doc, or multi-line qq{ } more readable than this.
>
> Can you give me an example of a HERE-doc? (What I tried to avoid is
> having ugly indentation-breaking tlobs.)print <<EOF; foo EOF
HERE-docs necessarily break indentation unless you strip it out manually (which is inefficient and ugly).
But two things that might make that look better are using qq// (to avoid having to escape quotes) and interpolating the variables:
. qq/." Generator: $self->{generator}\n/> I'll try to find something about qq{} in the docs.It's in perlop, but it's basically a fancy way of double-quoting, except that you get to choose the delimiter.
Show 7 quoted lines
> > > $text =~ s/([^\n]) *\n([^\n])/\1 \2/g; > > > > "." is the same as [^\n] (without the 's' modifier). > > But I need the (implicit) 's' modifier, otherwise the "\n" in the middle > is not interpreted correctly. This regsub is meant to unwrap the > paragraph and put it into a very long line (but leaving \n\n alone).
I think you might be confused about how the 's' modifier works. You are not using it, so '.' is the same as '[^\n]'. Perl will always match a newline if it's in your regex. If you specify 'm', then it will also allow '^' and '$' to match at line boundaries (instead of just at the beginning and end of the string).
-Peff