Re: How do get a specific version of a particular file?

From: Theodore Tso <tytso@mit.edu>
Date: Feb 28, 2007, 03:03 UTC
Message-ID: <20070228030347.GE2178@thunk.org>
In-Reply-To: <7vr6sb2e5m.fsf@assigned-by-dhcp.cox.net>

On Tue, Feb 27, 2007 at 06:45:41PM -0800, Junio C Hamano wrote:

Show 15 quoted lines

> Theodore Tso <tytso@mit.edu> writes:
> 
> > Well, the other design alternative is to make git-show take a list of
> > objects, so that
> >
> > 	git show v1.5.0..v1.5.0.1
> >
> > ends up displaying the same thing as
> >
> > 	git show `git-rev-list v1.5.0..v1.5.0.1`
> >
> > ... but I'm not really convinced that's really all that useful.  
> 
> I think we are better off doing "git show v1.5.0..v1.5.0.1" for
> that, but we do take multiple objects.

Not sure I understand what you mean?  That:

	git show v1.5.0..v1.5.0.1

should should show all the commits between v1.5.0 and v1.5.0.1, or just print the commit corresponding to v1.5.0.1 (and the v1.5.0 is completely meaningless?)

Show 10 quoted lines

> > Note the use of singular.  That would imply that it takes a single
> > object, and not a range of objects.  Of course, if the above behavior
> > were actually shown to be useful, man pages can always be easily
> > changed.  :-)
> 
> I find myself running "git show --stat v1.X.Y v1.X.Y+1" every
> time I tag a new release Y+2 to find out things like:
> 
> 	* Should I say "Git v1.5.1" or "GIT 1.5.1"?
> 	* Ah, I have to update GIT-VERSION-GEN, which I did, good.

But why not just type:

	git show --stat v1.X.Y+1

instead?  Or if you don't want the tag information, you could type:

	git show --stat v1.X.Y+1^{commit}

since

	git show --stat v1.5.0..v1.5.0.1
and
	git show --stat v1.4.4.0..v1.5.0.1
and
	git show --stat v1.0.0..v1.5.0.1

all print exactly the same thing!

Hence Linus's and my argument that as currently implemented the ".." operator to git doesn't make a lot of sense....

						- Ted