Re: [PATCH] Return error when not checking out an entry due to dirtiness.
Junio C Hamano <junkio@cox.net> wrote:
Show 34 quoted lines
> Without -f flag, 'git-checkout-index foo.c' issued an error message
> when foo.c already existed in the working tree and did not match index.
> However it did not return an error from the underlying checkout_entry()
> function and resulted in a successful exit(0).
>
> Signed-off-by: Junio C Hamano <junkio@cox.net>
>
> ---
>
> * I've made sure that the existing scripts do not use
> checkout-index without -f in a way that could be affected by
> this change. However, third-party scripts may be affected by
> this. Cogito and StGIT should be OK -- they either run
> checkout with -f, do not check the error return when it does
> not use -f, or runs checkout without -f in an empty working
> tree.
>
> checkout-index.c | 11 ++++++++---
> entry.c | 2 +-
> 2 files changed, 9 insertions(+), 4 deletions(-)
>
> 5a166f6a9d1b7ca2de673139fbfc4112b1b2e308
> diff --git a/checkout-index.c b/checkout-index.c
> --- a/checkout-index.c
> +++ b/checkout-index.c
> @@ -63,15 +63,20 @@ static int checkout_file(const char *nam
>
> static int checkout_all(void)
> {
> - int i;
> + int i, errs;
>
> - for (i = 0; i < active_nr ; i++) {
> + for (errs = i = 0; i < active_nr ; i++) {This is ugly. Why not just:
errs = 0;
for (i = 0; i < active_nr ; i++) { (errs is in no way the variable controlled by the for).
--
Dr. Horst H. von Brand User #22616 counter.li.org
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