[PATCH v3 01/14] refs.c make ref_transaction_create a wrapper to ref_transaction_update
Signed-off-by: Ronnie Sahlberg <sahlberg@google.com>
---
refs.c | 13 ++-----------
refs.h | 7 ++++---
2 files changed, 6 insertions(+), 14 deletions(-)
diff --git a/refs.c b/refs.c
index dfbf003..a9f91ab 100644
--- a/refs.c
+++ b/refs.c
@@ -3487,23 +3487,14 @@ int ref_transaction_create(struct ref_transaction *transaction,
int flags, const char *msg,
struct strbuf *err)
{
- struct ref_update *update;
-
if (transaction->state != REF_TRANSACTION_OPEN)
die("BUG: create called for transaction that is not open");
if (!new_sha1 || is_null_sha1(new_sha1))
die("BUG: create ref with null new_sha1");
- update = add_update(transaction, refname);
-
- hashcpy(update->new_sha1, new_sha1);
- hashclr(update->old_sha1);
- update->flags = flags;
- update->have_old = 1;
- if (msg)
- update->msg = xstrdup(msg);
- return 0;
+ return ref_transaction_update(transaction, refname, new_sha1,
+ null_sha1, flags, 1, msg, err);
}
int ref_transaction_delete(struct ref_transaction *transaction,
diff --git a/refs.h b/refs.h
index db463d0..495740d 100644
--- a/refs.h
+++ b/refs.h
@@ -283,9 +283,10 @@ struct ref_transaction *ref_transaction_begin(struct strbuf *err);
/*
* Add a reference update to transaction. new_sha1 is the value that
* the reference should have after the update, or zeros if it should
- * be deleted. If have_old is true, then old_sha1 holds the value
- * that the reference should have had before the update, or zeros if
- * it must not have existed beforehand.
+ * be deleted. If have_old is true and old_sha is not the null_sha1
+ * then the previous value of the ref must match or the update will fail.
+ * If have_old is true and old_sha1 is the null_sha1 then the ref must not
+ * already exist and a new ref will be created with new_sha1.
* Function returns 0 on success and non-zero on failure. A failure to update
* means that the transaction as a whole has failed and will need to be
* rolled back.
--
2.0.0.467.g08c0633
Ronnie Sahlberg <sahlberg@google.com>