Hello,
Is it expected for check-ignore to output included files (using a "!" prefix)?
Steps to reproduce:
git init foo
cd foo
touch bar
echo '/bar\n!/bar' > .gitignore
git add bar .gitignore
git commit -mbar
git check-ignore --verbose --no-index barActual behavior:
.gitignore:2:!/bar bar
exit code = 0
Expected behavior:
no output
exit code = 1
I tested with the next branch, which is currently at 8a191e187a9dca3d786c0197f9610e627b4f4137.
The man page of check-ignore says: « For each pathname [...], check whether the file is excluded by .gitignore [...] and output the path if it is excluded. » and: « If the pattern contained a ! prefix or / suffix, it will be preserved in the output. »
The man page of gitignore says: « An optional prefix "!" which negates the pattern; any matching file excluded by a previous pattern will become included again. »
I am not sure how I should understand this situation.
Best regards, Julien