[PATCH 2/2] Ensure git ls-tree exits with a non-zero exit code if read_tree_recursive fails.
In the case of a corrupt repository, git ls-tree may report an error but presently it exits with a code of 0.
This change uses the return code of read_tree_recursive instead.
Signed-off-by: Jon Seymour <jon.seymour@gmail.com>
---
builtin/ls-tree.c | 6 +++---
1 files changed, 3 insertions(+), 3 deletions(-)
Show changes to builtin/ls-tree.c +3 −3
diff --git a/builtin/ls-tree.c b/builtin/ls-tree.c
index f08c5b0..6d6c992 100644
--- a/builtin/ls-tree.c
+++ b/builtin/ls-tree.c
@@ -120,7 +120,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
{
unsigned char sha1[20];
struct tree *tree;
- int i, full_tree = 0;
+ int i, full_tree = 0, err;
const struct option ls_tree_options[] = {
OPT_BIT('d', NULL, &ls_options, "only show trees",
LS_TREE_ONLY),
@@ -173,7 +173,7 @@ int cmd_ls_tree(int argc, const char **argv, const char *prefix)
tree = parse_tree_indirect(sha1);
if (!tree)
die("not a tree object");
- read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
+ err = read_tree_recursive(tree, "", 0, 0, &pathspec, show_tree, NULL);
- return 0;
+ return err;
}
--
1.7.6.347.g6a5a9c