[PATCH] cherry_pick_list: quit early if one side is empty
The --cherry-pick logic starts by counting the commits on each side, so that it can filter away commits on the bigger one. However, so far it missed an opportunity for optimization: it doesn't need to do any work if either side is empty.
This in particular helps the common use-case 'git rebase -i HEAD~$n': it internally uses --cherry-pick, but since HEAD~$n is a direct ancestor the left side is always empty.
Signed-off-by: Thomas Rast <trast@student.ethz.ch>
---
On Saturday 20 February 2010 08:27:28 Jeff King wrote:
>
> From my reading of the code, that is right, but this is the first time I
> ever looked at it, so who knows? :)
Junio agreed too, so here's a real patch. To keep the complexity of git-rebase--interactive from exploding even further, you can drop the earlier one.
Show 8 quoted lines
> Does it really make sense to treat binary files as anything other than a
> blob for generating patch id? That is, should we simply turn it into:
>
> binary diff
> $from_sha1
> $to_sha1
>
> and hash that for the patch id?
I tend to agree, but I can't seem to find out what flags to flip :-(
revision.c | 3 +++
1 files changed, 3 insertions(+), 0 deletions(-)
diff --git a/revision.c b/revision.c
index 438cc87..29721ec 100644
--- a/revision.c
+++ b/revision.c
@@ -547,6 +547,9 @@ static void cherry_pick_list(struct commit_list *list, struct rev_info *revs)
right_count++;
}
+ if (!left_count || !right_count)
+ return;
+
left_first = left_count < right_count;
init_patch_ids(&ids);
if (revs->diffopt.nr_paths) {
--
1.7.0.139.gd1a75.dirty