From: Linus Torvalds Date: Mon, 13 Feb 2006 16:54:31 GMT Subject: Re: Quick question Message-ID: In-Reply-To: <43F0B577.4070608@gorzow.mm.pl> On Mon, 13 Feb 2006, Radoslaw Szkodzinski wrote: > > How to display ignored files of the whole project using only core git? > > I've tried: > > git-ls-files -o -i -X .git/info/exclude > > and it only showed me the excluded files in the current directory... Well, since you're telling it to only show excluded files, it will also only show excluded directories. Which is admittedly insane. You don't want to exclude directories. Or maybe you do, but then we should add the "/" to the end before we do the exclusion. This patch (untested) will never exclude directories. Which may or may not be the right thing. Junio? Others? Comments? Linus --- diff --git a/ls-files.c b/ls-files.c index 7024cf1..b923f92 100644 --- a/ls-files.c +++ b/ls-files.c @@ -276,8 +276,6 @@ static void read_directory(const char *p continue; len = strlen(de->d_name); memcpy(fullname + baselen, de->d_name, len+1); - if (excluded(fullname) != show_ignored) - continue; switch (DTYPE(de)) { struct stat st; @@ -304,6 +302,8 @@ static void read_directory(const char *p case DT_LNK: break; } + if (excluded(fullname) != show_ignored) + continue; add_name(fullname, baselen + len); } closedir(dir);