From: Felipe Contreras Date: Thu, 18 Apr 2013 11:15:36 GMT Subject: Re: Bug with rev-list --reverse? Message-ID: In-Reply-To: <20130418102644.GY2278@serenity.lan> On Thu, Apr 18, 2013 at 5:26 AM, John Keeping wrote: > On Thu, Apr 18, 2013 at 05:17:14AM -0500, Felipe Contreras wrote: >> If I do these: >> >> % git log --oneline -1 v1.8.1.5^..v1.8.1.6 >> % git log --oneline --reverse -1 v1.8.1.5^..v1.8.1.6 >> >> I expect to get a different output, and not both showing v1.8.1.6. >> Wouldn't you agree? > > I expect to get the same output. This is probably because I consider > --reverse to be an output filter. So I expect to show the commits > "v1.8.1.5^..v1.8.1.6 -1" which selects a single commit and then show > that in reverse order. How about this: % git log --oneline --reverse --max-count=1 v1.8.1.5^..v1.8.1.6 In this case --max-count is acting as "start from the first commit before the tip", not as "output a maximum of one commit". Given that the name is max-count, I expect it to be the later. And if max-count doesn't select a maximum of n commits, then what does? -- Felipe Contreras