From: Junio C Hamano Date: Thu, 12 Jun 2008 08:33:14 GMT Subject: Re: [PATCH] Improve sed portability Message-ID: <7vy75b833p.fsf@gitster.siamese.dyndns.org> In-Reply-To: <484FDB5D.7060606@viscovery.net> Johannes Sixt writes: > Chris Ridd schrieb: >> On Solaris /usr/bin/sed apparently fails to process input that doesn't >> end in a \n. Consequently constructs like >> >> re=$(printf '%s' foo | sed -e 's/bar/BAR/g' $) >> >> cause re to be set to the empty string. > > So does /usr/bin/sed of AIX 4.3! > >> @@ -73,7 +73,7 @@ resolve_relative_url () >> module_name() >> { >> # Do we have "submodule..path = $1" defined in .gitmodules file? >> - re=$(printf '%s' "$1" | sed -e 's/[].[^$\\*]/\\&/g') >> + re=$(printf "%s\n" "$1" | sed -e 's/[].[^$\\*]/\\&/g') > > You change sq into dq. Is this not dangerous? Shouldn't backslash-en be > hidden from the shell so that printf can interpret it? "\n" inside dq is _not_ interpreted by the shell (printf interprets it), but I tend to agree that using sq is worry-free and better. >> name=$( git config -f .gitmodules --get-regexp '^submodule\..*\.path$' | >> sed -n -e 's|^submodule\.\(.*\)\.path '"$re"'$|\1|p' ) > > I trust you have tested this. But I wonder whether this leaves a stray > newline in $re that gets in the way inside the sed expression... I suspect the very original was written (or copied from something that wrote) like this: re=$(echo -n "$1" | sed -e '...') and mechanically replaced to re=$(printf '%s' "$1" | sed -e '...') because "echo" is not quite portable. But the original misunderstands the command substitution. The trailing LF is removed by it, so as long as "$1" is a single line, $re will get a line without the trailing LF _anyway_.