From: Junio C Hamano Date: Sun, 13 Sep 2009 02:27:01 GMT Subject: Re: [PATCH] transport-helper.c: don't leak fdopen'd stream buffers Message-ID: <7vtyz760lm.fsf@alter.siamese.dyndns.org> In-Reply-To: <87hbv833kd.fsf@meyering.net> Jim Meyering writes: > diff --git a/transport-helper.c b/transport-helper.c > index f57e84c..0bbd014 100644 > --- a/transport-helper.c > +++ b/transport-helper.c > @@ -49,6 +49,7 @@ static struct child_process *get_helper(struct transport *transport) > if (!strcmp(buf.buf, "fetch")) > data->fetch = 1; > } > + fclose (file); > return data->helper; > } > > @@ -88,6 +89,7 @@ static int fetch_with_fetch(struct transport *transport, > if (strbuf_getline(&buf, file, '\n') == EOF) > exit(128); /* child died, message supplied already */ > } > + fclose (file); > return 0; > } The callchain of fetch_with_fetch() looks like: fetch_with_fetch() helper = get_helper(); --> get_helper() - start helper with start_command(); - read from helper->out until it sees an empty line; - break out of the loop; <-- return helper - file = xfdopen(helper->out) to get another FILE on the fd - read the rest of the output from helper->out via file It seems to me that the fclose() in get_helper() will close the underlying fd and would break the caller, no? I think "struct helper_data" should get a new FILE* field and once somebody creates a FILE* out of its helper->out, that FILE* can be passed around without a new xfdopen(). Or something like that. Who is responsible for closing the underlying helper->out fd in the start_command() API, by the way?