From: Junio C Hamano Date: Thu, 03 Jan 2013 15:34:53 GMT Subject: Re: [BUG] two-way read-tree can write null sha1s into index Message-ID: <7vehi2xote.fsf@alter.siamese.dyndns.org> In-Reply-To: <20130103083712.GC32377@sigill.intra.peff.net> Jeff King writes: > On Tue, Jan 01, 2013 at 02:24:46PM -0800, Junio C Hamano wrote: > >> Jeff King writes: >> >> > So I think we need to update twoway_merge to recognize unmerged entries, >> > which gives us two options: >> > >> > 1. Reject the merge. >> > >> > 2. Throw away the current unmerged entry in favor of the "new" entry >> > (when old and new are the same, of course; otherwise we would >> > reject). >> > >> > I think (2) is the right thing. >> >> As "--reset" in "read-tree --reset -u A B" is a way to say "we know >> we are based on A and we want to go to B no matter what", I agree we >> should not reject the merge. >> >> With -m instead of --reset, I am not sure what the right semantics >> should be, though. > > Good point; I was just thinking about the --reset case. > > With "-m", though, we could in theory carry over the unmerged entries > (again, assuming that "old" and "new" are the same; otherwise it is an > obvious reject). But those entries would be confused with any new > unmerged entries we create. It seems we already protect against this, > though: "read-tree -m" will not run at all if you have unmerged entries. > > Likewise, "checkout" seems to have similar protections. > > So I think it may be a non-issue. Yeah. Also earlier in the thread you mentioned three-way case, but I do not think we ever would want --reset with three trees, so I think that too is a non-issue for the same reason. I would still feel safer if we expressed the expectation of the callee in the code, perhaps like this in the two-way case: if (current->ce_flags & CE_CONFLICTED) { if (!o->reset) { ... either die or fail ... } else { ... your fix ... } }