From: René Scharfe Date: Sat, 13 Aug 2016 17:26:02 GMT Subject: Re: [PATCH] correct FLEXPTR_* example in comment Message-ID: <57AF582A.3050406@web.de> In-Reply-To: <20160813090947.uj6hurji5o6cwxge@sigill.intra.peff.net> Am 13.08.2016 um 11:09 schrieb Jeff King: > On Sat, Aug 13, 2016 at 11:01:21AM +0200, René Scharfe wrote: > >> This section is about "The FLEXPTR_* variants", so use FLEXPTR_ALLOC_STR >> in the example. > > Oops, yeah. Your patch is clearly an improvement. > > Since this is obviously an easy mistake to make (using one form rather > than the other), I wondered if the compiler would catch it. > > I think it would catch an accidental use of FLEXPTR instead of FLEX, > because it involves an attempted assignment of an array. Gcc 5.4 reports "invalid use of flexible array member". > But I don't > think we would catch the reverse; we'd just write the data directly on > top of the pointer. That would probably crash immediately at runtime, so > if you exercise the code at all in tests, it is OK. But something to be > aware of. No hint at compile time, segfaults at runtime. > I suppose it could assert(sizeof((x)->flexname) == FLEX_ALLOC) or > something, but I'm not sure if it is worth worrying about. You can't use sizeof with an actual flexible array. It only works if FLEX_ARRAY is defined as 1 (for platforms without native support), and perhaps also if it's 0. offsetof(struct x, arr) == sizeof(struct x) won't work either because of padding. I have no idea what you can do with a flexible array that would throw a compile error when done with a pointer. René