From: Derrick Stolee Date: Tue, 01 May 2018 12:26:47 GMT Subject: Re: [PATCH 4/9] get_short_oid: sort ambiguous objects by type, then SHA-1 Message-ID: <348f193f-47bb-112f-6ef5-571749bb01e2@gmail.com> In-Reply-To: <87a7tjzkdm.fsf@evledraar.gmail.com> On 5/1/2018 7:27 AM, Ævar Arnfjörð Bjarmason wrote: > On Tue, May 01 2018, Derrick Stolee wrote: > >> On 4/30/2018 6:07 PM, Ævar Arnfjörð Bjarmason wrote: >>> Since we show the commit data in the output that's nicely aligned once >>> we sort by object type. The decision to show tags before commits is >>> pretty arbitrary, but it's much less likely that we'll display a tag, >>> so if there is one it makes sense to show it first. >> Here's a non-arbitrary reason: the object types are ordered >> topologically (ignoring self-references): >> >> tag -> commit, tree, blob >> commit -> tree >> tree -> blob > Thanks. I'll add a patch with that comment to v2. > >>> @@ -421,7 +451,12 @@ static int get_short_oid(const char *name, int len, struct object_id *oid, >>> ds.fn = NULL; >>> advise(_("The candidates are:")); >>> - for_each_abbrev(ds.hex_pfx, show_ambiguous_object, &ds); >>> + for_each_abbrev(ds.hex_pfx, collect_ambiguous, &collect); >>> + QSORT(collect.oid, collect.nr, sort_ambiguous); >> I was wondering how the old code sorted by SHA even when the ambiguous >> objects were loaded from different sources (multiple pack-files, loose >> objects). Turns out that for_each_abbrev() does its own sort after >> collecting the SHAs and then calls the given function pointer only >> once per distinct object. This avoids multiple instances of the same >> object, which may appear multiple times across pack-files. >> >> I only ask because now we are doing two sorts. I wonder if it would be >> more elegant to provide your sorting algorithm to for_each_abbrev() >> and let it call show_ambiguous_object as before. >> >> Another question is if we should use this sort generally for all calls >> to for_each_abbrev(). The only other case I see is in >> builtin/revparse.c. > When preparing v2 I realized how confusing this was, so I'd added this > to the commit message of my WIP re-roll which should explain this: > > A note on the implementation: I started out with something much > simpler which just replaced oid_array_sort() in sha1-array.c with a > custom sort function before calling oid_array_for_each_unique(). But > then dumbly noticed that it doesn't work because the output function > was tangled up with the code added in fad6b9e590 ("for_each_abbrev: > drop duplicate objects", 2016-09-26) to ensure we don't display > duplicate objects. > > That's why we're doing two passes here, first we need to sort the list > and de-duplicate the objects, then sort them in our custom order, and > finally output them without re-sorting them. I suppose we could also > make oid_array_for_each_unique() maintain a hashmap of emitted > objects, but that would increase its memory profile and wouldn't be > worth the complexity for this one-off use-case, > oid_array_for_each_unique() is used in many other places. How would sorting in our custom order before de-duplicating fail the de-duplication? We will still pair identical OIDs as consecutive elements and oid_array_for_each_unique only cares about consecutive elements having distinct OIDs, not lex-ordered OIDs. Perhaps the noise is because we rely on oid_array_sort() to mark the array as sorted inside oid_array_for_each_unique(), but that could be remedied by calling our QSORT() inside for_each_abbrev() and marking the array as sorted before calling oid_array_for_each_unique(). (Again, my comments are not meant to block this series.) Thanks, -Stolee